x^2+2x-(2i-1)=0

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Solution for x^2+2x-(2i-1)=0 equation:


Simplifying
x2 + 2x + -1(2i + -1) = 0

Reorder the terms:
x2 + 2x + -1(-1 + 2i) = 0
x2 + 2x + (-1 * -1 + 2i * -1) = 0
x2 + 2x + (1 + -2i) = 0

Reorder the terms:
1 + -2i + 2x + x2 = 0

Solving
1 + -2i + 2x + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -2i + 2x + -1 + x2 = 0 + -1

Reorder the terms:
1 + -1 + -2i + 2x + x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2i + 2x + x2 = 0 + -1
-2i + 2x + x2 = 0 + -1

Combine like terms: 0 + -1 = -1
-2i + 2x + x2 = -1

Add '-2x' to each side of the equation.
-2i + 2x + -2x + x2 = -1 + -2x

Combine like terms: 2x + -2x = 0
-2i + 0 + x2 = -1 + -2x
-2i + x2 = -1 + -2x

Add '-1x2' to each side of the equation.
-2i + x2 + -1x2 = -1 + -2x + -1x2

Combine like terms: x2 + -1x2 = 0
-2i + 0 = -1 + -2x + -1x2
-2i = -1 + -2x + -1x2

Divide each side by '-2'.
i = 0.5 + x + 0.5x2

Simplifying
i = 0.5 + x + 0.5x2

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